Am 21.12.2011 23:25 schrieb Eric:
Is it true that if I want to create an array or arbitrary size such
as:
for a in range(n):
x.append(<some function...>)
I must do this instead?
x=[]
for a in range(n):
x.append(<some function...>)
Of course - your x must exist before using it.
> Now to my actual question. I need to do the above for multiple arrays
(all the same, arbitrary size). So I do this:
x=y=z=[]
for a in range(n):
x.append(<some function...>)
y.append(<some other function...>)
z.append(<yet another function...>)
Also, is there a more pythonic way to do "x=[], y=[], z=[]"?
You could do:
def create_xyz(n):
for a in range(n):
yield <some function...>, <some other function...>, \
<yet another function...>)
x, y, z = zip(*create_xyz(11))
or, if you want x, y, z to be lists,
x, y, z = [list(i) for i in zip(*create_xyz(11))]
.
Thomas
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