thank you, that makes sense. I should have posted this on another list (which I have now). and the change required is:
If your new array is x, you can use: numpy.ma.masked_array(x, mask=mask.mask) On Tue, Nov 22, 2011 at 11:48 AM, MRAB <pyt...@mrabarnett.plus.com> wrote: > On 21/11/2011 21:42, questions anon wrote: > >> I am trying to mask one array using another array. >> >> I have created a masked array using >> mask=MA.masked_equal(myarray,**0), >> that looks something like: >> [1 - - 1, >> 1 1 - 1, >> 1 1 1 1, >> - 1 - 1] >> >> I have an array of values that I want to mask whereever my mask has a a >> '-'. >> how do I do this? >> I have looked at >> http://www.cawcr.gov.au/bmrc/**climdyn/staff/lih/pubs/docs/**masks.pdf<http://www.cawcr.gov.au/bmrc/climdyn/staff/lih/pubs/docs/masks.pdf>but >> the command: >> >> d = array(a, mask=c.mask() >> >> results in this error: >> TypeError: 'numpy.ndarray' object is not callable >> >> I basically want to do exactly what that article does in that equation. >> >> Any feedback will be greatly appreciated. >> >> The article is using the Numeric module, but your error says that you're > using > the numpy module. They're not the same. > -- > http://mail.python.org/**mailman/listinfo/python-list<http://mail.python.org/mailman/listinfo/python-list> >
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