On Aug 19, 1:56 pm, Phil Thompson <p...@riverbankcomputing.com> wrote:
> On Fri, 19 Aug 2011 10:15:20 -0700 (PDT), Edgar Fuentes
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> <fuente...@gmail.com> wrote:
> > Dear friends,
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> > I need execute an external program from a gui using PyQt4, to avoid
> > that hang the main thread, i must connect the signal "finished(int)"
> > of a QProcess to work properly.
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> > for example, why this program don't work?
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> > from PyQt4.QtCore import QProcess
> > pro = QProcess() # create QProcess object
> > pro.connect(pro, SIGNAL('started()'), lambda
> > x="started":print(x)) # connect
> > pro.connect(pro, SIGNAL("finished(int)"), lambda
> > x="finished":print(x))
> > pro.start('python',['hello.py']) # star hello.py program
> > (contain print("hello world!"))
> > timeout = -1
> > pro.waitForFinished(timeout)
> > print(pro.readAllStandardOutput().data())
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> > output:
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> > started
> > 0
> > b'hello world!\n'
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> > see that not emit the signal finished(int)
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> Yes it is, and your lambda slot is printing "0" which is the return code
> of the process.
>
> Phil
Ok, but the output should be:
started
b'hello world!\n'
finished
no?.
thanks Phil
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