On Fri, 19 Aug 2011 10:15:20 -0700 (PDT), Edgar Fuentes
<fuente...@gmail.com> wrote:
> Dear friends,
>
> I need execute an external program from a gui using PyQt4, to avoid
> that hang the main thread, i must connect the signal "finished(int)"
> of a QProcess to work properly.
>
> for example, why this program don't work?
>
> from PyQt4.QtCore import QProcess
> pro = QProcess() # create QProcess object
> pro.connect(pro, SIGNAL('started()'), lambda
> x="started":print(x)) # connect
> pro.connect(pro, SIGNAL("finished(int)"), lambda
> x="finished":print(x))
> pro.start('python',['hello.py']) # star hello.py program
> (contain print("hello world!"))
> timeout = -1
> pro.waitForFinished(timeout)
> print(pro.readAllStandardOutput().data())
>
> output:
>
> started
> 0
> b'hello world!\n'
>
> see that not emit the signal finished(int)
Yes it is, and your lambda slot is printing "0" which is the return code
of the process.
Phil
--
http://mail.python.org/mailman/listinfo/python-list
