Frank Millman wrote:
> If I really wanted to be 100% safe, how about this -
>
> def get_int(s):
> if '.' in s:
> num, dec = s.split('.', 1)
> if dec != '':
> if int(dec) != 0:
> raise ValueError('Invalid literal for int')
> return int(num)
> return int(s)Consider what happens if you pass s = "42.-0". -- Steven -- http://mail.python.org/mailman/listinfo/python-list
