On Jul 23, 9:42 am, Chris Angelico <ros...@gmail.com> wrote:
> On Sat, Jul 23, 2011 at 4:53 PM, Frank Millman <fr...@chagford.com> wrote:
> > The problem with that is that it will silently ignore any non-zero
> > digits after the point. Of course int(float(x)) does the same, which I
> > had overlooked.
>
> If you know that there will always be a trailing point, you can trim
> off any trailing 0s, then trim off a trailing '.', and then cast to
> int:
>
> int(s.rstrip('0').rstrip('.'))
>I like it. 100% solution to the problem, and neater than the alternatives. Thanks Frank -- http://mail.python.org/mailman/listinfo/python-list
