On 01/-10/-28163 02:59 PM, RVince wrote:
s = "C:\AciiCsv\Gravity_Test_data\A.csv"
f = open(s,"r")
How do I obtain the full pathname given the File, f? (which should
equal "C:\AciiCsv\Gravity_Test_data"). I've tried all sorts of stuff
and am just not finding it. Any help greatly appreciated !
I saw lots of responses, but I don't think anybody pointed out that the
filename is probably invalid. This particular string will work, but if
you have a directory that starts with a T or an N, you may get some
surprises. The backslash is treated specially in a literal string.
When building a Windows directory name in a literal string, you
generally need to do one of three things:
1) use raw literals
2) double the backslash
3) use a forward slash
DaveA
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