Ha! You;re right -- but is there a way to get it without the filename appended at the end?
On May 24, 11:52 am, Tim Golden <m...@timgolden.me.uk> wrote: > On 24/05/2011 16:36, RVince wrote: > > > s = "C:\AciiCsv\Gravity_Test_data\A.csv" > > f = open(s,"r") > > > How do I obtain the full pathname given the File, f? (which should > > equal "C:\AciiCsv\Gravity_Test_data"). I've tried all sorts of stuff > > and am just not finding it. Any help greatly appreciated ! > > You're going to kick yourself: > > f.name > > TJG -- http://mail.python.org/mailman/listinfo/python-list