On Thu, 28 Apr 2011 01:49:33 +0100, Chris Angelico <ros...@gmail.com>
wrote:
On Thu, Apr 28, 2011 at 10:42 AM, Rusty Scalf <iai-...@sonic.net> wrote:
list1 = ['pig', 'horse', 'moose']
list2 = ['62327', '49123', '79115']
n = 2
s2 = "list" + `n`
a = s2[list1.index('horse')]
print a
s2 is a string with the value "list2"; this is not the same as the
variable list2. You could use eval to convert it, but you'd do better
to have a list of lists:
lists = [
['pig', 'horse', 'moose']
['62327', '49123', '79115']
]
Then you could use:
n = 2
a = lists[n][list1.index('horse')]
*cough* I think you mean
n = 1
a = lists[n][list[0].index('horse')]
The alternative would be to have a dictionary of lists:
lists = {
"list1": ['pig', 'horse', 'moose'],
"list2": ['62327', '49123', '79115']
}
n = 2
s2 = "list" + str(n)
a = lists[s2][lists["list1"].index('horse')]
Both of these can be made less ugly if the list you want to index into
isn't one of the lists you might want to look up, but that's just a detail.
--
Rhodri James *-* Wildebeest Herder to the Masses
--
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