Chris Angelico wrote:
> Rusty Scalf wrote:
>> list1 = ['pig', 'horse', 'moose']
>> list2 = ['62327', '49123', '79115']
>> n = 2
>> s2 = "list" + `n`
I would prefer the clearer
s2 = "list" + str(n)
or
s2 = "list%s" % n
>> a = s2[list1.index('horse')]
>> print a
>
> s2 is a string with the value "list2"; this is not the same as the
> variable list2. You could use eval to convert it, but you'd do better
> to have a list of lists:
>
> lists = [
> ['pig', 'horse', 'moose']
> ['62327', '49123', '79115']
> ]
You forgot a comma after the first `]', to separate the list elements.
A way to reuse the existing code is
lists = [list1, list2]
> Then you could use:
> n = 2
> a = lists[n][list1.index('horse')]
That would throw an IndexError exception, though, since list indexes are
0-based, and this list has only two items (so the highest index is 1, not
2).
But even if this was fixed, this could still throw a ValueError exception
if there was no 'horse' in `list1'. While you could catch that –
needle = 'horse'
try:
a = lists[n][list1.index(needle)]
except ValueError:
a = 'N/A'
– perhaps a better way to store this data is a dictionary:
data = {
'pig': '62327',
'horse': '49123',
'moose': '79115'
}
print data.get('horse')
print data.get('cow')
print data.get('cow', 'N/A')
Such a dictionary can be built from the existing lists as well:
data = dict(zip(list1, list2))
print data
print data.get('horse', 'N/A')
HTH
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PointedEars
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