On 2/11/2011 4:24 PM, LL.Snark wrote:
Hi,I'm looking for a pythonic way to translate this short Ruby code : t=[6,7,8,6,7,9,8,4,3,6,7] i=t.index {|x| x<t.first} If you don't know Ruby, the second line means : What is the index, in array t, of the first element x such that x<t[0].
What does Ruby do if there is no such element? For Python, the answer should be either None or ValueError.
If can write it in python several ways : t=[6,7,8,6,7,9,8,4,3,6,7] i=0 while t[i]>=t[0] : i+=1
This will raise IndexError when i gets too big.
... not pythonic I think... Or : t=[6,7,8,6,7,9,8,4,3,6,7] i=[j for j in range(len(t)) if t[j]<t[0]][0]
This will raise IndexError if the list is empty. -- Terry Jan Reedy -- http://mail.python.org/mailman/listinfo/python-list
