Hi,
I'm looking for a pythonic way to translate this short Ruby code :
t=[6,7,8,6,7,9,8,4,3,6,7]
i=t.index {|x| x<t.first}
If you don't know Ruby, the second line means :
What is the index, in array t, of the first element x such that x<t[0].
If can write it in python several ways :
t=[6,7,8,6,7,9,8,4,3,6,7]
i=0
while t[i]>=t[0] : i+=1
... not pythonic I think...
Or :
t=[6,7,8,6,7,9,8,4,3,6,7]
i=[j for j in range(len(t)) if t[j]<t[0]][0]
...too cryptic...
I'm using Python 3.
Thx
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