2011/2/5 Lisa Fritz Barry Griffin <lisaochba...@gmail.com>:
> Hi there,
>
> How can I do this in a one liner:
>
> maxCountPerPhraseWordLength = {}
> for i in range(1,MAX_PHRASES_LENGTH+1):
> maxCountPerPhraseWordLength[i] = 0
>
> Thanks!
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> http://mail.python.org/mailman/listinfo/python-list
>
Hi,
as has been already suggested, using collections.defaultdict may be
appropriate, but it's fairly straightforward to mimic the original
code with a generator expression in dict(...)
maxCountPerPhraseWordLength = dict((i,0) for i in range(1,MAX_PHRASES_LENGTH+1))
or with a dict literal (in newer python versions)
maxCountPerPhraseWordLength = {i:0 for i in range(1,MAX_PHRASES_LENGTH+1)}
(possibly using xrange for larger dicts - in pyton 2)
hth,
vbr
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