Lisa Fritz Barry Griffin wrote:
> How can I do this in a one liner:
>
> maxCountPerPhraseWordLength = {}
> for i in range(1,MAX_PHRASES_LENGTH+1):
> maxCountPerPhraseWordLength[i] = 0
You can init a dictionary with zeroes with
d = dict.fromkeys(range(1, MAX_PHRASES_LENGTH+1), 0)
but this won't work as expected for mutable values:
>>> d = dict.fromkeys(range(5), [])
>>> d
{0: [], 1: [], 2: [], 3: [], 4: []}
>>> d[0].append(42)
>>> d
{0: [42], 1: [42], 2: [42], 3: [42], 4: [42]}
Oops! all values refere to the same list.
Instead you can use a defaultdict which adds items as needed:
>>> from collections import defaultdict
>>> d = defaultdict(list)
>>> d
defaultdict(<type 'list'>, {})
>>> d[0].append(42)
>>> d
defaultdict(<type 'list'>, {0: [42]})
>>> d[7].append(123)
>>> d
defaultdict(<type 'list'>, {0: [42], 7: [123]})
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