Thanks Stephen. It's really nice of you.
I have not understood everything though. (I have never used a context
manager before.)
Here are some comments :
timeout = s.gettimeout() # Is that the default timeout ?
s.settimeout(3) # I guess this is a 3 second timeout
s.recv(1024)
s.settimeout(timeout) # You change it back ?
So with a while loop, it should be :
timeout = s.gettimeout()
s.settimeout(3)
b=time.clock()
while time.clock()-b<3 :
data=s.recv(1024)
s.settimeout(timeout)
Am I right ?
Thanks again,
Dwayne
2011/2/3 Stephen Hansen <me+list/pyt...@ixokai.io>
> On 2/3/11 10:13 AM, Dwayne Blind wrote:
> > Thanks for your answer. I don't want to reset my socket. I want to apply
> > the timeout to the rcv method only.
>
> Setting the timeout does not "reset [your] socket", I don't think. And I
> get that you want to only timeout recv... that's why I pointed out its a
> socket method, not an argument to recv. If you don't want it to apply to
> everything else, you just have to be sure to change it back after recv.
>
> Just:
> timeout = s.gettimeout()
> s.settimeout(3)
> s.recv(1024)
> s.settimeout(timeout)
>
> Personally, I'd prefer to do:
>
> with timeout(s, 3):
> s.recv(1024)
>
> That's a lot more clear, and I'd roll this context manager to accomplish
> it:
>
> --- start
>
> from contextlib import contextmanager
>
> @contextmanager
> def timeout(sock, timeout):
> old_timeout = sock.gettimeout()
> sock.settimeout(timeout)
> try:
> yield sock
> finally:
> sock.settimeout(old_timeout)
>
> --- end
>
> The contextmanager decorator is an easy/quick way of making a context
> manager. Everything up until the yield is executed before the 'with'
> block is run, and everything after the yield is executed after the
> 'with' block concludes.
>
> If the with block throws an exception, it'll be catchable at the yield
> point.
>
> --
>
> Stephen Hansen
> ... Also: Ixokai
> ... Mail: me+list/python (AT) ixokai (DOT) io
> ... Blog: http://meh.ixokai.io/
>
>
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