"Rob Richardson" <rob.richard...@rad-con.com> writes:
You shouldn't top-post!
> Arnaud,
>
> Wouldn't your first suggestion exit after the first element in iterable?
Yes, after printing that element, which is what the code I quoted did.
> And would your second suggestion throw an exception after normal
> processing of all elements in the interator?
No. It would have the same behaviour as the first one.
> RobR
>
> -----Original Message-----
>
>
> I missed the start of this discussion but there are two simpler ways:
>
> def func(iterable):
> for x in iterable:
> print(x)
> return
> raise ValueError("... empty iterable")
>
> Or using 3.x's next's optional second argument:
>
> _nonext=object()
> def func(iterable):
> x = next(iter(iterable), _nonext)
> if x is _nonext:
> raise ValueError("... empty iterable")
> print(x)
>
> --
> Arnaud
--
Arnaud
--
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