Please don't top-post.
Rob Richardson wrote:
-----Original Message-----
I missed the start of this discussion but there are two simpler ways:
def func(iterable):
for x in iterable:
print(x)
return
raise ValueError("... empty iterable")
Or using 3.x's next's optional second argument:
_nonext=object()
def func(iterable):
x = next(iter(iterable), _nonext)
if x is _nonext:
raise ValueError("... empty iterable")
print(x)
> Arnaud,
>
> Wouldn't your first suggestion exit after the first element in
> iterable?
No, it hit's return instead.
> And would your second suggestion throw an exception after normal
> processing of all elements in the interator?
Looks like the second solution doesn't process the entire iterable, just
it's first element.
~Ethan~
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