TomF wrote: > I'm aggravated by this behavior in python: > > x = "4" > print x < 7 # prints False > > The issue, of course, is comparisons of incompatible types. In most > languages this throws an error (in Perl the types are converted > silently). In Python this comparison fails silently. The > documentation says: "objects of different types *always* compare > unequal, and are ordered consistently but arbitrarily." > > I can't imagine why this design decision was made. I've been bitten by > this several times (reading data from a file and not converting the > numbers before comparison). Can I get this to throw an error instead > of failing silently?
This change would break a lot of code, so it could not be made within the 2.x series. However: Python 3.1.1+ (r311:74480, Nov 2 2009, 15:45:00) [GCC 4.4.1] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> "4" < 7 Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: unorderable types: str() < int() Peter -- http://mail.python.org/mailman/listinfo/python-list
