On 06/12/2010 16:59, TomF wrote:
I'm aggravated by this behavior in python:
x = "4"
print x < 7 # prints False
The issue, of course, is comparisons of incompatible types. In most
languages this throws an error (in Perl the types are converted
silently). In Python this comparison fails silently. The documentation
says: "objects of different types *always* compare unequal, and are
ordered consistently but arbitrarily."
I can't imagine why this design decision was made. I've been bitten by
this several times (reading data from a file and not converting the
numbers before comparison). Can I get this to throw an error instead of
failing silently?
Yes: switch to python 3 where this does throw an exception:
Python 3.1.2 (r312:79149, Mar 21 2010, 00:41:52
Type "help", "copyright", "credits" or "license
7 < "eight"
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unorderable types: int() < str()
TJG
--
http://mail.python.org/mailman/listinfo/python-list
