MATLABdude wrote: > On Nov 17, 10:53 am, Arnaud Delobelle <arno...@gmail.com> wrote: >> I guess that the step is supposed to be h, so you should write: >> xx = range(-kappa, kappa+1, h) > > This is what I have in the source code: > ---8<---8<---8<---8<--- > h = 0.105069988414 > xx = range(-kappa, kappa+1, h) > ---8<---8<---8<---8<--- > > This is what Python says: ValueError: range() step argument must not > be zero > > Can step not be a float value?
Indeed. Older Pythons will warn you and then try to convert the arguments to integers >>> range(1.0) __main__:1: DeprecationWarning: integer argument expected, got float [0] and in 2.7 or 3.x you'll get a type error: >>> range(1.0) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: range() integer end argument expected, got float. Try numpy.arange() instead: >>> numpy.arange(0, 1, .1) array([ 0. , 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9]) -- http://mail.python.org/mailman/listinfo/python-list
