On 8/11/10 1:47 PM, Bradley Hintze wrote:
Hi all,
Is there a way that I can startup my script and pass it a file? For example:
~$ python myscript.py mytext.txt
and then access mytext.txt in myscript.py?
As a long shot, for myscript.py I tried
def __init__(fle):
print fle
expecting the full path to mytext.txt to be printed but that didn't work.
Obviously I've never done this. I hope the above makes sense. any help
will be greatly appreciated.
http://docs.python.org/library/sys#sys.argv
I do recommend using argparse to process command line arguments, even for the
simplest cases:
http://docs.python.org/library/argparse
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is made terrible by our own mad attempt to interpret it as though it had
an underlying truth."
-- Umberto Eco
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