Bradley Hintze wrote: > Hi all, > > Is there a way that I can startup my script and pass it a file? For > example: > > ~$ python myscript.py mytext.txt > > and then access mytext.txt in myscript.py? > > As a long shot, for myscript.py I tried > > def __init__(fle): > print fle > > expecting the full path to mytext.txt to be printed but that didn't work. > > Obviously I've never done this. I hope the above makes sense. any help > will be greatly appreciated. > > Thanks,
You are looking for sys.argv: $ cat tmp.py import sys print sys.argv $ python tmp.py one two 'many arguments' ['tmp.py', 'one', 'two', 'many arguments'] Around that simple mechanism fancier libraries have been built: http://docs.python.org/library/argparse.html Peter -- http://mail.python.org/mailman/listinfo/python-list
