Thanks, both of the methods work fine: open(os.path.expandvars("${SOMETHING}/sc_1.sh"), "r") OR infile = open(os.path.join(env, 'sc_1.sh'),"r")
// Naderan *Mahmood; ________________________________ From: Christian Heimes <li...@cheimes.de> To: python-list@python.org Sent: Fri, June 11, 2010 2:05:15 PM Subject: Re: passing environment variable path to open command Am 11.06.2010 10:39, schrieb Mahmood Naderan: > Hi, > I am new to python so my question may be very basic. > Suppose I have a file (sc_1.sh) which the path to that file is in system path: > SOMETHING=/home/mahmood/scripts > > Now I want to open that file with respect to the environment variable: > import os > env = os.getenv("SOMETHING") > print env > infile = open("env/sc_1.sh","r") > > But here is the error I get: > /home/mahmood/scripts > Traceback (most recent call last): > File "test.py", line 7, in <module> > infile = open("env/sc_1.sh","r") > IOError: [Errno 2] No such file or directory: 'env/sc_1.sh' > > How can I use such variable in open file command? > Thanks, How about: open(os.path.expandvars("${SOMETHING}/sc_1.sh"), "r") See http://docs.python.org/library/os.path.html#os.path.expandvars -- http://mail.python.org/mailman/listinfo/python-list
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