Mahmood Naderan wrote:
Hi,
I am new to python so my question may be very basic.
Suppose I have a file (sc_1.sh) which the path to that file is in
system path:
SOMETHING=/home/mahmood/scripts
Now I want to open that file with respect to the environment variable:
import os
env = os.getenv("SOMETHING")
print env
infile = open("env/sc_1.sh","r")
But here is the error I get:
/home/mahmood/scripts
Traceback (most recent call last):
File "test.py", line 7, in <module>
infile = open("env/sc_1.sh","r")
IOError: [Errno 2] No such file or directory: 'env/sc_1.sh'
How can I use such variable in open file command?
Thanks,
*// Naderan *Mahmood;*
import os
infile = open(os.path.join(env, 'sc_1.sh'),"r")
JM
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