s...@sig.for.address (Victor Eijkhout) writes:
> I have two long ints, both too long to convert to float, but their ratio
> is something reasonable. How can I compute that? The obvious "(1.*x)/y"
> does not work.
The math.log function has a special hack for long ints, that might help:
Python 2.6.2 (r262:71600, Jan 25 2010, 18:46:47)
>>> from math import *
>>> a = log(3**100000)
>>> a
109861.22886681097
>>> b = log(3**100001)
>>> exp(b-a)
2.9999999999994813
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