Peter Otten writes: > Victor Eijkhout wrote: > > > I have two long ints, both too long to convert to float, but their > > ratio is something reasonable. How can I compute that? The obvious > > "(1.*x)/y" does not work. > > >>> import fractions > >>> x = 12345 * 10**1000 > >>> y = 765 * 10**1000 > >>> float(x) > Traceback (most recent call last): > File "<stdin>", line 1, in <module> > OverflowError: long int too large to convert to float > >>> fractions.Fraction(x, y) > Fraction(823, 51) > >>> float(_) > 16.137254901960784
Logarithms agree to 13 decimal digits or so: >>> math.exp(math.log(x) - math.log(y)) 16.13725490196353 -- http://mail.python.org/mailman/listinfo/python-list
