On Apr 8, 6:06 pm, monkeys paw <mon...@joemoney.net> wrote: > On 4/7/2010 1:08 PM, Peter Pearson wrote: > > > > > On Tue, 06 Apr 2010 23:16:18 -0400, monkeys paw<mon...@joemoney.net> wrote: > >> I have the following acre meter which works for integers, > >> how do i convert this to float? I tried > > >> return float ((208.0 * 208.0) * n) > > >>>>> def s(n): > >> ... return lambda x: (208 * 208) * n > >> ... > >>>>> f = s(1) > >>>>> f(1) > >> 43264 > >>>>> 208 * 208 > >> 43264 > >>>>> f(.25) > >> 43264 > > > The expression "lambda x: (208 * 208) * n" is independent of x. > > Is that what you intended? > > Seems i should have done this: > g = lambda x: 208.0 * 208.0 * x > g(1) > 43264.0
Yes, but then what is the 'n' for. When you do that, you are not using it, and it is still confusing. Regards, Pat -- http://mail.python.org/mailman/listinfo/python-list
