Hello Johan,
thanks to you (and everyone else who answered) for your effort.
Johan Grönqvist <johan.gronqv...@gmail.com> writes:
> Manuel Graune skrev:
>> Manuel Graune <manuel.gra...@koeln.de> writes:
>>
>> Just as an additional example, let's assume I'd want to add the area of
>> to circles.
>> [...]
>> which can be explained to anyone who knows
>> basic math and is not at all interested in
>> python.
>>
>
> Third attempt. The markup now includes tagging of different parts of
> the code, and printing parts of the source based on a tag.
>
after playing around for a while, this is what I finally ended up with:
8<--------8<-------- source ---8<--------
#! /usr/bin/python
## Show
# List of all imports:
from __future__ import with_statement, print_function
from math import pi as PI
import sys
##
class Source_Printer(object):
def __init__(self):
self.is_printing= False
with open(sys.argv[0]) as file:
self.lines= iter(file.readlines())
for line in self.lines:
if line.startswith("print_source"):
break
elif line == "##\n":
self.is_printing= False
elif line.startswith("## Show"):
print("\n")
self.is_printing= True
elif self.is_printing:
print(line,end="")
def __call__(self):
for line in self.lines:
if line == "##\n" or line.startswith("print_source"):
if self.is_printing:
self.is_printing= False
break
else:
self.is_printing= False
elif line.startswith("## Show"):
print("\n")
self.is_printing= True
elif self.is_printing:
print(line, end="")
print_source= Source_Printer()
## Show
#Calculation of first Area:
d1= 3.0
A1= d1**2 * PI / 4.0
##
print_source()
print ("Area of Circle 1:\t", A1)
## Show
#Calculation of second area:
d2= 5.0
A2= d2**2 * PI / 4.0
##
# This is a comment that won't be printed
print_source()
print ("Area of Circle 2:\t", A2)
# This is another one
Sum_Of_Areas= A1 + A2
print ("Sum of areas:\t", Sum_Of_Areas)
8<--------8<-------- result: ---8<--------
# List of all imports:
from __future__ import with_statement, print_function
from math import pi as PI
import sys
#Calculation of first Area:
d1= 3.0
A1= d1**2 * PI / 4.0
Area of Circle 1: 7.06858347058
#Calculation of second area:
d2= 5.0
A2= d2**2 * PI / 4.0
Area of Circle 2: 19.6349540849
Sum of areas: 26.7035375555
8<--------8<-------- result: ---8<--------
Regards,
Manuel
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