Oops, minor update:
>>> def split_number(string):
... output = [string[0]]
... for character in string[1:]:
... if character.isdigit() != output[-1].isdigit():
... if output[-1].isdigit() is True:
... output[-1] = int(output[-1])
... output.append('')
... output[-1] += character
... return tuple(output)
...
>>> split_number('si_pos_99_rep_1_0.ita')
('si_pos_', 99, '_rep_', 1, '_', 0, '.ita')
Cheers,
Xav
On Fri, Apr 2, 2010 at 8:26 PM, Xavier Ho <cont...@xavierho.com> wrote:
> Best I can come up with:
>
> >>> def split_number(string):
> ... output = [string[0]]
> ... for character in string[1:]:
> ... if character.isdigit() != output[-1].isdigit():
> ... output.append('')
> ... output[-1] += character
> ... return tuple(output)
> ...
> >>> split_number('si_pos_99_rep_1_0.ita')
>
> ('si_pos_', '99', '_rep_', '1', '_', '0', '.ita')
>
> Cheers,
> Xav
>
>
> On Fri, Apr 2, 2010 at 8:12 PM, Thomas Heller <thel...@ctypes.org> wrote:
>
>> Maybe I'm just lazy, but what is the fastest way to convert a string
>> into a tuple containing character sequences and integer numbers, like
>> this:
>>
>>
>> 'si_pos_99_rep_1_0.ita' -> ('si_pos_', 99, '_rep_', 1, '_', 0, '.ita')
>>
>> Thanks for ideas,
>> Thomas
>>
>> --
>> http://mail.python.org/mailman/listinfo/python-list
>>
>
>
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