Pete Emerson wrote:
> In a module, how do I create a conditional that will do something
> based on whether or not another module has been loaded?
>
> Suppose I have the following:
>
> import foo
> import foobar
>
> print foo()
> print foobar()
>
> ########### foo.py
> def foo:
> return 'foo'
>
> ########### foobar.py
> def foobar:
> if foo.has_been_loaded(): # This is not right!
> return foo() + 'bar' # This might need to be foo.foo() ?
> else:
> return 'bar'
>
> If someone is using foo module, I want to take advantage of its
> features and use it in foobar, otherwise, I want to do something else.
> In other words, I don't want to create a dependency of foobar on foo.
>
> My failed search for solving this makes me wonder if I'm approaching
> this all wrong.
>
> Thanks in advance,
> Pete
One way would be
if "foo" in sys.modules:
# foo was imported
However that won't get you all the way, since sys.modules["foo"] will be
set even if the importing statement was
from foo import this, that, the_other
So you might want to add
foo = sys.modules["foo"]
inside the function.
regards
Steve
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