On Mar 5, 11:24 am, Pete Emerson <pemer...@gmail.com> wrote:
> In a module, how do I create a conditional that will do something
> based on whether or not another module has been loaded?
>
> Suppose I have the following:
>
> import foo
> import foobar
>
> print foo()
> print foobar()
>
> ########### foo.py
> def foo:
> return 'foo'
>
> ########### foobar.py
> def foobar:
> if foo.has_been_loaded(): # This is not right!
> return foo() + 'bar' # This might need to be foo.foo() ?
> else:
> return 'bar'
>
> If someone is using foo module, I want to take advantage of its
> features and use it in foobar, otherwise, I want to do something else.
> In other words, I don't want to create a dependency of foobar on foo.
>
> My failed search for solving this makes me wonder if I'm approaching
> this all wrong.
>
> Thanks in advance,
> Pete
Aha, progress. Comments appreciated. Perhaps there's a different and
more conventional way of doing it than this?
def foobar():
import sys
if 'foomodule' in sys.modules.keys():
import foomodule
return foomodule.foo() + 'bar'
else:
return 'bar'
--
http://mail.python.org/mailman/listinfo/python-list
