Jean-Michel Pichavant <jeanmic...@sequans.com> writes:
> Paulo Repreza wrote:
>> Greetings,
>>
>> I'm having problems with a little script that I'm trying to finish,
>> I don't know if I'm in the right track but I know somebody is going
>> to help me.
>>
>> The script:
>>
>> # Import modules random for function randint
>>
>> import random
>>
>> # Generating a constant.
>>
>> var = 65
>>
>> # Generating a random number.
>> ranum = random.randint(1,100)
>>
>> #Creating while loop. Stops until var == ranum
>> while var != ranum:
>> if var == ranum:
>> print var, 'equals to:', ranum
>> else:
>> print var, 'does not equal to:', ranum
>>
>> ########## End of Script ###########
>>
>>
>> What I'm trying to do is to print the new value that ranum generates
>> if the condition is not met. So far if you run the script it prints
>> the same value over and over again, making in an infinite loop. What
>> can I do in order to print out the new value generated every time
>> the condition is not met?
>>
>> Thanks!
>>
>> Paulo Repreza
> in your script you generate the random number only once, no wonder it
> keep being the same value over & over.
>
> # Initialize ranum with a random number
> ranum = random.randint(1,100)
>
> #Creating while loop. Stops until var == ranum
> while var != ranum:
> if var == ranum:
> print var, 'equals to:', ranum
> else:
> print var, 'does not equal to:', ranum
> ranum = random.randint(1,100) # generate a new number, that's the
> missing line in your script
>
> JM
And a more idiomatic way of writing this in Python would be, I guess:
import random
var = 65
while True:
ranum = random.randint(1, 100)
if var == ranum:
print var, 'equals to:', ranum
break
else:
print var, 'does not equal to:', ranum
(following up from a FU as I can't see the OP)
--
Arnaud
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