l = ['asc', '*nbh*', 'jlsdjfdk', 'ikjh', '*jkjsdfjasd*', 'rewr']
Notice that some of the items in the list start and end with an '*'. I wish to
construct a new list, call it 'n' which is all the members of l that start and
end with '*', with the '*'s removed.
So in the case above n would be ['nbh', 'jkjsdfjasd']
the following works:
r = re.compile('\*(.+)\*')
def f(s):
m = r.match(s)
if m:
return m.group(1)
else:
return ''
n = [f(x) for x in l if r.match(x)]
But it is inefficient, because it is matching the regex twice for each item,
and it is a bit ugly.
You can skip the function by writing that as
n = [r.match(s).group(1) for s in l if r.match(s)]
but it doesn't solve your match-twice problem.
I'd skip regexps completely and do something like
n = [s[1:-1] for s in l
if s.startswith('*')
and s.endswith('*')
]
And this is coming from a guy that tends to overuse regexps :)
-tkc
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