I have a problem and I am trying to find a solution to it that is both
efficient and elegant.
I have a list call it 'l':
l = ['asc', '*nbh*', 'jlsdjfdk', 'ikjh', '*jkjsdfjasd*', 'rewr']
Notice that some of the items in the list start and end with an '*'. I wish to
construct a new list, call it 'n' which is all the members of l that start and
end with '*', with the '*'s removed.
So in the case above n would be ['nbh', 'jkjsdfjasd']
the following works:
r = re.compile('\*(.+)\*')
def f(s):
m = r.match(s)
if m:
return m.group(1)
else:
return ''
n = [f(x) for x in l if r.match(x)]
But it is inefficient, because it is matching the regex twice for each item,
and it is a bit ugly.
I could use:
n = []
for x in keys:
m = r.match(x)
if m:
n.append(m.group(1))
It is more efficient, but much uglier.
Does anyone have a better solution?
Thank,
-EdK
Ed Keith
e_...@yahoo.com
Blog: edkeith.blogspot.com
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