elements_present = lambda seq, match: any(((x in match) for x in seq))
On Mon, 14 Sep 2009 19:08:59 -0600, Oltmans <rolf.oltm...@gmail.com> wrote:
Hello,
Is there someway I can improve the following code(pythonically)?
(Copying from IDLE)
match=[1,2,3,4,5]
def elementsPresent(aList):
result=False
if not aList:
return False
for e in aList:
if e in match:
result=True
else:
result = False
return result
elementsPresent([6,7,8,9,5]) # should return True because 5 is
present in list named match.
Is there somehow I can improve code in elementsPresent()? I'm not a
very good programmer but I sense that idea of using a variable named
'result' inside elementsPresent() doesn't sound very good. Any ideas
will be highly appreciated.
Thanks,
Oltmans
--
Kind regards, Sergey Simonenko.
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