On Aug 18, 3:51 pm, "Jan Kaliszewski" <z...@chopin.edu.pl> wrote: > 18-08-2009 o 22:32:55 Robert Dailey <rcdai...@gmail.com> wrote: > > > > > > > On Aug 18, 3:31 pm, Duncan Booth <duncan.bo...@invalid.invalid> wrote: > >> Robert Dailey <rcdai...@gmail.com> wrote: > >> > Hello, > > >> > I want to simply wrap a function up into an object so it can be called > >> > with no parameters. The parameters that it would otherwise have taken > >> > are already filled in. Like so: > > >> > print1 = lambda: print( "Foobar" ) > >> > print1() > > >> > However, the above code fails with: > > >> > File "C:\IT\work\distro_test\distribute_radix.py", line 286 > >> > print1 = lambda: print( "Foobar" ) > >> > ^ > >> > SyntaxError: invalid syntax > > >> > How can I get this working? > > >> def print1(): > >> print "Foobar" > > >> It looks like in your version of Python "print" isn't a function. It > >> always > >> helps if you say the exact version you are using in your question as the > >> exact answer you need may vary. > > > I'm using Python 2.6. And using the legacy syntax in the lambda does > > not work either. > > In Python 1.x/2.x 'print' is a keyword-based statement, not a function > -- then you cannot use it in lambda (which in Python is limited to > single expressions, and statements are not allowed in it). > > You can try using sys.stdout.write() instead. > > > I want to avoid using a def if possible. > > But what for? Usualy def is more readable than lambda and it's not worth > to lose readibility just to save a few keystrokes. > > Cheers, > *j > > -- > Jan Kaliszewski (zuo) <z...@chopin.edu.pl>
I posted a bit earlier than you did. See my previous post. Thanks for the help. -- http://mail.python.org/mailman/listinfo/python-list
