In article
<c217c4a4-b891-469e-af4f-4e44e2c95...@z24g2000yqb.googlegroups.com>,
Robert Dailey <rcdai...@gmail.com> wrote:
> On Aug 18, 3:31 pm, Duncan Booth <duncan.bo...@invalid.invalid> wrote:
> > Robert Dailey <rcdai...@gmail.com> wrote:
> > > Hello,
> >
> > > I want to simply wrap a function up into an object so it can be called
> > > with no parameters. The parameters that it would otherwise have taken
> > > are already filled in. Like so:
> >
> > > print1 = lambda: print( "Foobar" )
> > > print1()
> >
> > > However, the above code fails with:
> >
> > > File "C:\IT\work\distro_test\distribute_radix.py", line 286
> > > print1 = lambda: print( "Foobar" )
> > > ^
> > > SyntaxError: invalid syntax
> >
> > > How can I get this working?
> >
> > def print1():
> > print "Foobar"
> >
> > It looks like in your version of Python "print" isn't a function. It always
> > helps if you say the exact version you are using in your question as the
> > exact answer you need may vary.
>
> I'm using Python 2.6. And using the legacy syntax in the lambda does
> not work either. I want to avoid using a def if possible. Thanks.
The problem is that in Python 2 print is a statement, not a function.
That should work fine in Python 3 where print *is* a function. In 2.x,
you can wrap print in a function or use something like:
>>> import sys
>>> print1 = lambda: sys.stdout.write("Foobar\n")
>>> print1()
Foobar
or the pprint library module or various other solutions.
--
Ned Deily,
n...@acm.org
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