On Jul 15, 2009, at 1:43 PM, Jean-Michel Pichavant wrote:
Hrvoje Niksic wrote: [snip]Note that in Python A or B is in fact not equivalent to not(not A and not B).>>> l = [(True, True), (True, False), (False, True), (False, False)] >>> for p in l: ... p[0] or p[1] [snip] Did I make twice the same obvious error ?
Try again with:
l = [('foo','bar'), ('foo', ''), ('', 'bar'), ('', '')]
-Miles
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