Hrvoje Niksic wrote:
[snip]
Note that in Python A or B is in fact not equivalent to not(not A and
not B).
>>> l = [(True, True), (True, False), (False, True), (False, False)]
>>> for p in l:
...     p[0] or p[1]
...
True
True
True
False
>>> for p in l:
...     not(not p[0] and not p[1])
...
True
True
True
False
>>>
Did I make twice the same obvious error ?

JM
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