On Jun 30, 5:34 pm, Mitchell L Model <mlmli...@comcast.net> wrote:
> Allow me to add to my previous question that certainly the superclass
> methods can be called explicitly without resorting to super(), e.g.:
>
> class C(A, B):
> def __init__(self):
> A.__init__(self)
> B.__init__(self)
>
> My question is really whether there is any way of getting around the
> explicit class names by using super()
Yes there is: just make sure that all subclasses also call super.
class A:
def __init__(self):
super().__init__()
print('A')
class B:
def __init__(self):
super().__init__()
print('B')
class C(A, B):
def __init__(self):
super().__init__()
print('C')
Bam, that's it.
What's happening is that A's super calls B. That is likely to seem
wrong to someone who is very familiar with OOP, but it's how Python's
MI works.
Read this essay/rant that explains how super works and why the author
thinks it's not useful. Then ignore the last part, because I and many
others have found it very useful, desipte its drawbacks.
http://fuhm.net/super-harmful/
Carl Banks
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