On Jun 24, 11:27 am, Chris Rebert <c...@rebertia.com> wrote: > On Wed, Jun 24, 2009 at 10:50 AM, David<ww...@yahoo.com> wrote: > > hello, > > > I have a url that is "http://query.directrdr.com/ptrack? > > pid=225&v_url=http:// > >www.plentyoffish.com&keyword=flowers&feed=1&ip=12.2.2.2&said=$said". > > If I open it on a browser, I can get its contents without any > > problem. > > However, if I use following code, > > > import urllib2 > > > url = 'http://query.directrdr.com/ptrack?pid=225&v_url=http:// > >www.plentyoffish.com&keyword=flowers&feed=1&ip=12.2.2.2&said=$said' > > > xml = urllib2.urlopen(url).read() > > > then I get an exception of > > > File "/usr/lib/python2.5/urllib2.py", line 1082, in do_open > > raise URLError(err) > > urllib2.URLError: <urlopen error (-2, 'Name or service not known')> > > Unable to reproduce with either urllib or urllib2's urlopen(). I get > some XML back without error both ways. Using Python 2.6.2 on Mac OS X. > > Cheers, > Chris > --http://blog.rebertia.com- Hide quoted text - > > - Show quoted text -
Thanks Aahz. And thanks Chris. The XML content is what I am looking for. I use Python 2.5. Maybe I should update to 2.6.2? Python version problem? -- http://mail.python.org/mailman/listinfo/python-list
