On Wed, Jun 24, 2009 at 10:50 AM, David<ww...@yahoo.com> wrote: > hello, > > I have a url that is "http://query.directrdr.com/ptrack? > pid=225&v_url=http:// > www.plentyoffish.com&keyword=flowers&feed=1&ip=12.2.2.2&said=$said". > If I open it on a browser, I can get its contents without any > problem. > However, if I use following code, > > > import urllib2 > > > url = 'http://query.directrdr.com/ptrack?pid=225&v_url=http:// > www.plentyoffish.com&keyword=flowers&feed=1&ip=12.2.2.2&said=$said' > > > xml = urllib2.urlopen(url).read() > > > then I get an exception of > > > File "/usr/lib/python2.5/urllib2.py", line 1082, in do_open > raise URLError(err) > urllib2.URLError: <urlopen error (-2, 'Name or service not known')>
Unable to reproduce with either urllib or urllib2's urlopen(). I get some XML back without error both ways. Using Python 2.6.2 on Mac OS X. Cheers, Chris -- http://blog.rebertia.com -- http://mail.python.org/mailman/listinfo/python-list
