On Jan 24, 10:39 am, Benjamin Peterson <benja...@python.org> wrote:
> andrew cooke <andrew <at> acooke.org> writes:
>
>
>
> > Hi,
>
> > I have some 3.0 code, which I would like to make work with 2.6.
> > However, there does not seem to be support for the new super() (no
> > args) via __future__. Is that correct? If so, what's the best way to
> > handle this?
>
> Just use the two argument super(): super(MyClass, instance) It's supported in
> both versions.
Thanks. Any idea how to deal with ABCs? It's sufficient to use a
simple class, but I want to expose an ABC in 3.0 as it will make it
easier for others to extend.
Unfortunately, "metaclass=" is a syntax error in 2.6 so the following
still fails:
from sys import version
if version.startswith('2.'):
class Matcher():
pass
else:
class Matcher(metaclass=ABCMeta):
pass
Andrew
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