On Dec 29, 1:01 am, scsoce <scs...@gmail.com> wrote: > I have a function return a reference, and want to assign to the > reference, simply like this: > >>def f(a) > return a > b = 0 > * f( b ) = 1* > but the last line will be refused as "can't assign to function call". > In my thought , the assignment is very nature, but why the interpreter > refused to do that ? > > thks
Probably the closest thing you are going to get in Python would be the following: >>> class C: ... pass ... >>> def f(a): ... return a ... >>> b = C() >>> b.value = 0 >>> b.value 0 >>> f(b).value = 1 >>> b.value 1 But as others have pointed out, Python is not C/C++, and shouldn't be treated as such. -- http://mail.python.org/mailman/listinfo/python-list