On Oct 17, 4:34 pm, JD <[EMAIL PROTECTED]> wrote: > Hi, > > Thanks, > > It works for this example, > > but if I add another item ['e', 'd']: > [['a', 'b'], \ > ['c', 'd'], \ > ['e', 'f'], \ > ['a', 'g'], \ > ['e', 'k'], \ > ['c', 'u'], \ > ['b', 'p'],\ > ['e', 'd']] > > The result is > set(['a', 'p', 'b', 'g']), set(['e', 'c', 'u', 'd']), set(['k', 'e', > 'd', 'f']) > > The right result should be: > > ['a', 'p', 'b', 'g'], ['c', 'u', 'e', 'd', 'k', 'f'] > > JD > > On Oct 17, 3:00 pm, Mensanator <[EMAIL PROTECTED]> wrote: > > > > > On Oct 17, 3:20 pm, JD <[EMAIL PROTECTED]> wrote: > > > > Hi, > > > > I need help for a task looks very simple: > > > > I got a python list like: > > > > [['a', 'b'], ['c', 'd'], ['e', 'f'], ['a', 'g'], ['e', 'k'], ['c', > > > 'u'], ['b', 'p']] > > > > Each item in the list need to be merged. > > > > For example, 'a', 'b' will be merged, 'c', 'd' will be merged. > > > > Also if the node in the list share the same name, all these nodes need > > > be merged. > > > > For example, ['a', 'b'], ['a', 'g'] ['b', 'p'] will be merged to ['a', > > > 'b', 'g', 'p'] > > > > The answer should be: > > > > [['a', 'b', 'g', 'p'], ['c', 'd', 'u'], ['e', 'f', 'k']]
Well, you should have asked for that, if that's what you wanted. > > > > Anyone has a solution? > > > A = [['a', 'b'], \ > > ['c', 'd'], \ > > ['e', 'f'], \ > > ['a', 'g'], \ > > ['e', 'k'], \ > > ['c', 'u'], \ > > ['b', 'p']] > A.sort() > > merged = [] > > > for i in A: > > if len(merged)==0: > > merged.append(set(i)) > > else: > > gotit = False > > for k,j in enumerate(merged): > > u = j.intersection(set(i)) > > if len(u): > > merged[k] = j.union(set(i)) > > gotit = True > > if not gotit: > > merged.append(set(i)) > > > print merged > > > ## > > ## [set(['a', 'p', 'b', 'g']), set(['c', 'u', 'd']), set(['k', 'e', > > 'f'])] > > ## ## [set(['a', 'p', 'b', 'g']), set(['c', 'e', 'd', 'f', 'u', 'k'])] > > > > Thanks, > > > > JD -- http://mail.python.org/mailman/listinfo/python-list
