On 16 Oct, 18:53, "Diez B. Roggisch" <[EMAIL PROTECTED]> wrote: > Astley Le Jasper schrieb: > > > > > On 16 Oct, 16:52, Carsten Haese <[EMAIL PROTECTED]> wrote: > >> Astley Le Jasper wrote: > >>> Sorry for the numpty question ... > >>> How do you find the reference name of an object? > >>> So if i have this > >>> bob = modulename.objectname() > >>> how do i find that the name is 'bob' > >> Why do you need to find that? You know that its name is 'bob'. > > >> -- > >> Carsten Haesehttp://informixdb.sourceforge.net > > > I'm creating mulitple instances, putting them in a list, iterating > > through the list to send them to some functions where process them > > with some instance specific parameters. Something along the lines of: > > > bob = someobject() > > harry = someobject() > > fred = someobject() > > > parameterdict = {'bob':(0,1,2),'harry':(3,4,5),'fred':(6,7,8)} > > people_list = (bob, harry, fred) > > > for person in people_list: > > add_parameters(person) > > > def add_parameters(person) > > mytuple = parameterdict[??????instance.name????] > > person.x = mytuple[0] > > person.y = mytuple[1] > > person.z = mytuple[2] > > > ... alternatively there is probably a very much easier way of doing > > it. > > Why not simply do > > bob = someobject(0, 1, 2) > > ? > > Diez
Because that was pseudo code to demonstrate what I was trying to achieve. The parameters are more complicated than that. -- http://mail.python.org/mailman/listinfo/python-list
