gaurav kashyap wrote: > HI all, > i have two python programs as 1.py and 2.py > > 1.py > import os > import sys > processID=os.spawnl(os.P_WAIT,'/usr/local/bin/python','python','/ > mywork/2.py ' + 'hi') > > 2.py > import sys > domain= str(sys.argv[1] ) > print domain > > IN LINUX > while executing 1.py,the argument 'hi' is not passed to the 2.py and > error message is displayed as : > python: can't open file '/mywork/2.py'.
Did you cut and paste that? I would expect the message to be python: can't open file '/mywork/2.py hi'. or similar, i. e. the script name is assumed to be '/mywork/2.py hi'. You have to pass arguments to the 2.py script as separate arguments to os.spawnl() os.spawnl(os.P_WAIT,'/usr/local/bin/python','python','/mywork/2.py', 'hi') Peter -- http://mail.python.org/mailman/listinfo/python-list
