HI all, i have two python programs as 1.py and 2.py 1.py import os import sys processID=os.spawnl(os.P_WAIT,'/usr/local/bin/python','python','/ mywork/2.py ' + 'hi')
2.py import sys domain= str(sys.argv[1] ) print domain IN LINUX while executing 1.py,the argument 'hi' is not passed to the 2.py and error message is displayed as : python: can't open file '/mywork/2.py'.If i execute the program from shell like: python 2.py hi,then it works fine IN WINDOWS this is working fine PLEASE HELP. thanks gaurav -- http://mail.python.org/mailman/listinfo/python-list
