Joal Heagney wrote:
Bengt Richter wrote:
On Fri, 01 Apr 2005 07:46:41 GMT, Joal Heagney <[EMAIL PROTECTED]>
wrote:
Oh goddammmnitttt. I seem to be doing this a lot today. Look below
for the extra addition to the code I posted.
Joal Heagney wrote:
Here's my contribution anycase:
count = 0
# Get first input
name = raw_input("Guess my name: ")
# Give the sucker two extra goes
while count < 2:
# Check the value of name
if name == 'Ben':
print "You're right!"
break
else:
name = raw_input("Try again: ")
# Here's the bit I missed out.
count += 1
# Of course, we haven't checked the sucker's last guess
# so we have to do that now.
if count == 2:
if name == 'Ben':
print "You're right!"
else:
print "No more tries for you!!!"
Hope this helps.
Joal
GRRRRRRRR.
Need something more straightforward, e.g., a wrapped one-liner:
>>> def guess(n=3): print ("You're right!", 'No more tries for
you!!!')[n-1 in
... (x for x in xrange(n) for t in [raw_input('Guess my name:
')=='Ben']
... if not t or iter([]).next())]
Okay, now in my opinion, that's just too complex to give to a newbie as
a suggested implementation. :)
Joal
I suppose this would be far too easy to understand, then:
pr =['Guess my name', 'Wrong, try again', 'Last chance']
for p in pr:
name = raw_input(p+": ")
if name == "Ben":
print "You're right!"
break
else:
print "Loser: no more tries for you"
regards
Steve
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