Joal Heagney wrote:
Bengt Richter wrote:
On Fri, 01 Apr 2005 07:46:41 GMT, Joal Heagney <[EMAIL PROTECTED]> wrote:
Oh goddammmnitttt. I seem to be doing this a lot today. Look below for the extra addition to the code I posted.
Joal Heagney wrote:
Here's my contribution anycase:
count = 0 # Get first input name = raw_input("Guess my name: ") # Give the sucker two extra goes while count < 2: # Check the value of name if name == 'Ben': print "You're right!" break else: name = raw_input("Try again: ")
# Here's the bit I missed out. count += 1
# Of course, we haven't checked the sucker's last guess # so we have to do that now. if count == 2: if name == 'Ben': print "You're right!" else: print "No more tries for you!!!"
Hope this helps. Joal
GRRRRRRRR.
Need something more straightforward, e.g., a wrapped one-liner:
>>> def guess(n=3): print ("You're right!", 'No more tries for you!!!')[n-1 in
... (x for x in xrange(n) for t in [raw_input('Guess my name: ')=='Ben']
... if not t or iter([]).next())]
Okay, now in my opinion, that's just too complex to give to a newbie as a suggested implementation. :)
Joal
I suppose this would be far too easy to understand, then:
pr =['Guess my name', 'Wrong, try again', 'Last chance'] for p in pr: name = raw_input(p+": ") if name == "Ben": print "You're right!" break else: print "Loser: no more tries for you"
regards Steve
THIS is why I like python! There's always a simple, easy to understand way to do something. If it looks complex, then there must me something wrong.
Joal -- http://mail.python.org/mailman/listinfo/python-list
